Since I need to recalculate my required additional spring rate that I need to use to get a wheel rate of my chosen 233lb/in (equivalent to a 28.7mm TB) or close enough to, I'm going to need to add a 360lb/in coil over (either a 350 or 375 will be settled on).
So the combined spring rate (coilover and standard torsion bar) would be equivalent to about 600lb/in.
Numerous bits of research have hinted at 65% of spring rate as being a very good starting point for damping and having twice as much rebound damping as there is bump damping.
So I'm guessing that 65% is applied to the rebound damping, because if it's applied to the bump valving, then there would be 780lb/in worth of rebound damping.
Any comments or thoughts?
*** Apologies for persistent use of imperial measurements, despite being a metric person 99% of the time, imperial measurements just work for me better when talking suspension forces
![Confused :?](./images/smilies/icon_confused.gif)
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Bilstein Damper Valving Forces:
Valve #10 Force in Newtons 800 Force in Pounds 180
Valve #20 Force in Newtons 1200 Force in Pounds 270
Valve #30 Force in Newtons 1600 Force in Pounds 360
Valve #35 Force in Newtons 1850 Force in Pounds 416
Valve #40 Force in Newtons 2100 Force in Pounds 472
Valve #45 Force in Newtons 2350 Force in Pounds528
Valve #50 Force in Newtons 2600 Force in Pounds 585
Valve #55 Force in Newtons 2900 Force in Pounds 652
Valve #60 Force in Newtons 3200 Force in Pounds 720
Valve #70 Force in Newtons 3800 Force in Pounds 855
So if I have the equivalent of about 600lb/in spring, 65% of that is 390lb, so a bit more than a #30 valve. Half of 390 is 195, so a bit more than a #10 valve.
A reasonable interpretation of what's going on and a some sort of starting point????